[n+(1-n)]+[2n+(2-n)]=

Solution for [n+(1-n)]+[2n+(2-n)]= equation:

Simplifying
[n + (1 + -1n)] + [2n + (2 + -1n)] = 0

Remove parenthesis around (1 + -1n)
[n + 1 + -1n] + [2n + (2 + -1n)] = 0

Reorder the terms:
[1 + n + -1n] + [2n + (2 + -1n)] = 0

Combine like terms: n + -1n = 0
[1 + 0] + [2n + (2 + -1n)] = 0
[1] + [2n + (2 + -1n)] = 0
1 + [2n + (2 + -1n)] = 0

Remove parenthesis around (2 + -1n)
1 + [2n + 2 + -1n] = 0

Reorder the terms:
1 + [2 + 2n + -1n] = 0

Combine like terms: 2n + -1n = 1n
1 + [2 + 1n] = 0

Remove brackets around [2 + 1n]
1 + 2 + 1n = 0

Combine like terms: 1 + 2 = 3
3 + 1n = 0

Solving
3 + 1n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 1n = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 1n = 0 + -3
1n = 0 + -3

Combine like terms: 0 + -3 = -3
1n = -3

Divide each side by '1'.
n = -3

Simplifying
n = -3